X^2-x+15=(x-3)(x-5)

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Solution for X^2-x+15=(x-3)(x-5) equation: 



X^2-X+15=(X-3)(X-5)

We move all terms to the left:

X^2-X+15-((X-3)(X-5))=0

We add all the numbers together, and all the variables

X^2-1X-((X-3)(X-5))+15=0

We multiply parentheses ..

X^2-((+X^2-5X-3X+15))-1X+15=0



We calculate terms in parentheses: -((+X^2-5X-3X+15)), so:

(+X^2-5X-3X+15)

We get rid of parentheses

X^2-5X-3X+15

We add all the numbers together, and all the variables

X^2-8X+15

Back to the equation:

-(X^2-8X+15)



We add all the numbers together, and all the variables

X^2-1X-(X^2-8X+15)+15=0

We get rid of parentheses

X^2-X^2-1X+8X-15+15=0

We add all the numbers together, and all the variables

7X=0

X=0/7

X=0

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